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The Pirates have not clinched a non-losing season

nl_standingsThe newspapers here are full of news that the Pittsburgh Pirates (Major League Baseball) have broken a twenty-year reign of mediocrity by guaranteeing a non-losing season.  Since they have won 81 games in a 162 game season, that seems self-evident.

But those of us in operations research know enough to check out the details before leaping to a conclusion.  Consider the following situation:

1) The Pirates proceed to lose all their remaining games to end up at 81-81.

2) St. Louis and Cincinnati pass the Pirates, to win the division and the first wild-card.

3) Arizona ends up at 81-81 also, with all other teams (except division winners) with a worse record.

The Pirates would then play Arizona a one-game tie-breaker to determine who the second wild-card team is.  Suppose (horrors!) they lose again.  Where does the game count?  It turns out that tie-breaking  games count in the regular season records, as Wikipedia confirms.  So Pittsburgh would end up 81-82, for another losing season.  Note that it has to be a one-game tie-breaker:  subsequent playoff games are not included in regular season records.

I don’t think anyone is losing sleep over this possibility.  But a correct computer system for determining clinching of non-losing seasons would have to take this into account.   Having worked on such a system for another professional sports league, I can assure you that all the difficulty is in these near (but not quite) impossible events.  99% of the code handles cases that have never occurred, and are unlikely to occur in our lifetimes.

Note that if Pittsburgh wins one more game, then they are guaranteed a winning season:  a tie-breaker can’t turn their record into a losing (or .500) season.

Update 9/9: With the win tonight, the Pirates guarantee a winning season.  Now the streak is truly broken!  Go Bucs!

 

{ 4 } Comments

  1. Laura McLay | September 4, 2013 at 4:05 pm | Permalink

    Please don’t mathematically analyze Cubs’ records in current or past seasons – that will be even more depressing than the Pirates’ history ;-)

  2. Alex Fuller | September 4, 2013 at 5:54 pm | Permalink

    I like the idea that 99% of computer code handles exceptions. I’d love processes so thorough that they handle exceptions as good as a bug-free (or at least a less buggy) computer program.

    And I’m still a Cubs fan, even if the analysis isn’t pretty.

  3. yeah | September 5, 2013 at 4:16 pm | Permalink

    so um when they win their next game all of this “work” you did becomes completely irrelevant. nice. cool blog post bro.

  4. Michael Trick | September 5, 2013 at 4:36 pm | Permalink

    You can see my post in two ways: you can see it as specific to the Pirates, in which case the time-value of the post is indeed quite short. Or you can see it as a more general comment on the difficulty in determining things like clinching, elimination or guaranteeing a particular result in complicated systems. I prefer the latter interpretation: it lasts longer!